5x^2+4x=2-5x

Solution for 5x^2+4x=2-5x equation:

5x^2+4x=2-5x

We move all terms to the left:

5x^2+4x-(2-5x)=0

We add all the numbers together, and all the variables

5x^2+4x-(-5x+2)=0

We get rid of parentheses

5x^2+4x+5x-2=0

We add all the numbers together, and all the variables

5x^2+9x-2=0

a = 5; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·5·(-2)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-11}{2*5}=\frac{-20}{10}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+11}{2*5}=\frac{2}{10}
=1/5
$